越活越难 發表於 2023-9-11 00:00:00

dedecms 列表页,频道页获取当前栏目的父栏目名称的实现方法

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        代码如下:</p>
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        <br>
        //获取上级栏目名称 <br>
        if ( ! function_exists('GetParentTypename')) <br>
        { <br>
        function GetParentTypename($id){ <br>
        global $dsql ; <br>
        $reid = $dsql-&gt;GetOne("SELECT reid FROM wz_arctype where id=@me"); <br>
        $reid = $reid['reid']; <br>
        $row1 = $dsql-&gt;GetOne("SELECT typename FROM wz_arctype where id=$reid"); <br>
        return $row1['typename']; <br>
        } <br>
        } </p>
<p>
        <br style='font-family: tahoma, arial, "Microsoft YaHei"; font-size: 14px;'><br style='font-family: tahoma, arial, "Microsoft YaHei"; font-size: 14px;'><span style='font-family: tahoma, arial, "Microsoft YaHei"; font-size: 14px;'>列表或频道页调用方法 </span></p>
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        <p class="right">
                <span><u>复制代码</u></span></p>
        <p>
                代码如下:</p>
</div>
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        {dede:field.typeid function="GetParentTypename(@me)"/}</p>
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