92. 反转链表 II
<pre><code class="language-js">var reverseBetween = function(head, left, right) {if(!head)return null;
let ret=new ListNode(-1,head),pre=ret,cnt=right-left+1;
while(--left){
pre=pre.next;
}
pre.next=reverse(pre.next,cnt);
return ret.next;
}
var reverse=function(head,n){
let pre=null,cur=head;
while(n--){
=
}
head.next=cur;
return pre;
}
</code></pre><br><br>
来源：https://www.cnblogs.com/KooTeam/p/19837076
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