237.删除链表中的节点
<p>237.删除链表中的节点</p><pre><code class="language-js">/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} node
* @return {void} Do not return anything, modify node in-place instead.
*/
var deleteNode = function(node) {
node.val=node.next.val
node.next=node.next.next
};
</code></pre><br><br>
来源：https://www.cnblogs.com/KooTeam/p/18664088
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