237.删除链表中的节点

逆天七劍合璧

237.删除链表中的节点

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
/**
 * @param {ListNode} node
 * @return {void} Do not return anything, modify node in-place instead.
 */
var deleteNode = function(node) {
    node.val=node.next.val
    node.next=node.next.next
};

来源：https://www.cnblogs.com/KooTeam/p/18664088