查看: 103|回覆: 0

Leetcode 86 分割链表

[複製鏈接]

2

主題

0

回帖

0

積分

热心网友

金币
0
閲讀權限
220
精華
0
威望
0
贡献
0
在線時間
0 小時
註冊時間
2008-12-3
發表於 2021-6-26 21:39:00 | 顯示全部樓層 |閲讀模式

  JAVA:

        public final ListNode partition(ListNode head, int x) {
            ListNode leftHead = new ListNode(), rightHead = new ListNode(),
                    left = leftHead, right = rightHead;
            while (head != null) {
                if (head.val < x) {
                    left.next = head;
                    left = left.next;
                } else {
                    right.next = head;
                    right = right.next;
                }
                head = head.next;
            }
            right.next = null;
            left.next = rightHead.next;
            return leftHead.next;
        }

  JS:

/**
 * Definition for singly-linked list.
 * function ListNode(val, next) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.next = (next===undefined ? null : next)
 * }
 */
/**
 * @param {ListNode} head
 * @param {number} x
 * @return {ListNode}
 */
var partition = function (head, x) {
    let leftHead = new ListNode(), rightHead = new ListNode(),
        left = leftHead, right = rightHead;
    while (head != null) {
        if (head.val < x) {
            left.next = head;
            left = left.next;
        } else {
            right.next = head;
            right = right.next;
        }
        head = head.next;
    }
    right.next = null;
    left.next = rightHead.next;
    return leftHead.next;
};

回覆

使用道具 舉報

您需要登錄後才可以回帖 登錄 | 立即注册

本版積分規則

相关侵权、举报、投诉及建议等,请发 E-mail:qiongdian@foxmail.com

Powered by Discuz! X5.0 © 2001-2026 Discuz! Team.

在本版发帖返回顶部